Do the math

Barry

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I need a good mathematician to give me a formula for figuring out how fast a Viper can accelerate in 200’. If the Viper goes 0-92.78 in 660’ how fast was it going at the 200 foot mark?
 

Mike_W

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If all things were equal, it was going 28.11 mph. But they aren't.

Mike
 

Vic

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I think you would have to plot it on a graph, and show the acceleration curve. Can't extrapolate, does not compute. "Get back to the ship, Will Robinson!" [waving arms wildly]
 

BruceW

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A rough estimate would be to find the average torque over the rpm range used and then calculate the acceleration (as if it were constant over that rpm range). Accel=Torque*drive train ratio in first gear*radius of tire/(mass of the car). Your velocity change is then accel*time...or your velocity = initial velocity+accel*time (since the initial velocity).....just make sure your units are consistent
 

BruceW

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...forgot the distance calc part.
Distance is then distance=initial velocity*time + accel* time squared/2. Set the distance at 200ft and assume your starting velocity is zero so the time to 200 ft is the square root of (2 * 200ft/accel)
 

joe117

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You might just be able to get an approximation by figuring 1G acceleration. That would be 32ft/sec/sec.

It works out to about 3 seconds and 65mph for 1G acceleration to 200 feet.

That sound's a little fast doesn't it? Oh well.
 

Bonkers

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For a Stock Gen2 RT:
I got 63.52mph @ 4.469sec @ 199.63ft, but I couldn't translate that into a reasonable, reusable formula - at least not this week...
 

GR8_ASP

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The following are measured from an 1/4 mile run:

60 Ft............ 2.021 sec
0-60 mph......... 3.85 sec
200 ft........... 4.0 sec
330 ft........... 5.347 sec
8.01 s 94.01 mph in the 1/8 mile
1000 ft.......... 10.281 sec
12.17 s @ 120.54 mph in the 1/4 mile

Hope that helps.
 

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