I need a good mathematician to give me a formula for figuring out how fast a Viper can accelerate in 200’. If the Viper goes 0-92.78 in 660’ how fast was it going at the 200 foot mark?
I think you would have to plot it on a graph, and show the acceleration curve. Can't extrapolate, does not compute. "Get back to the ship, Will Robinson!" [waving arms wildly]
A rough estimate would be to find the average torque over the rpm range used and then calculate the acceleration (as if it were constant over that rpm range). Accel=Torque*drive train ratio in first gear*radius of tire/(mass of the car). Your velocity change is then accel*time...or your velocity = initial velocity+accel*time (since the initial velocity).....just make sure your units are consistent
...forgot the distance calc part.
Distance is then distance=initial velocity*time + accel* time squared/2. Set the distance at 200ft and assume your starting velocity is zero so the time to 200 ft is the square root of (2 * 200ft/accel)
For a Stock Gen2 RT:
I got 63.52mph @ 4.469sec @ 199.63ft, but I couldn't translate that into a reasonable, reusable formula - at least not this week...
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